return MediaMetadata( title=title, year=year, resolution=resolution, source=source, codec=codec, extension=ext ) Quiromancia Francisco Rodriguez Libros Pdf 12 Apr 2026
def parse_filename(raw_filename: str) -> MediaMetadata: """ Parses a messy release filename into structured metadata. Example Input: 'foxter.and.max.2019.webrip720pcmmp4' Example Output: MediaMetadata(title='Foxter and Max', year=2019, ...) """ # Normalize separators (dots, underscores, spaces) to single spaces clean_name = re.sub(r'[._]', ' ', raw_filename) # Regex pattern to capture Title, Year, Source, Resolution, Codec, Extension # Logic: # 1. Title is everything before the year. # 2. Year is 4 digits. # 3. Source (Webrip, Bluray). # 4. Resolution (720p, 1080p). # 5. Codec/Container at the end. pattern = r"(?P<title>.*?)\s*(?P<year>\d4)\s*(?P<source>webrip|bluray|hdtv|dvdrip)\s*(?P<resolution>\d3,4p)?(?P<codec>[\w]+)?\.(?P<ext>\w+)$" match = re.search(pattern, clean_name, re.IGNORECASE) if not match: raise ValueError(f"Could not parse filename: raw_filename") Kids - Box Jasmin Vol1
@dataclass class MediaMetadata: title: str year: int resolution: str source: str codec: str extension: str
import re from dataclasses import dataclass
Since "Foxter and Max" is an animated movie, and the string contains typical "pirated" file tags (WEBRip, resolution, codec), the most logical and "good" feature to create is a .
# --- Demonstration --- raw_input = "foxter.and.max.2019.webrip720pcmmp4"
Here is a Python implementation of this feature: