class FGHCalculator: def __init__(self): self.steps = 0 self.max_steps = 10000 # Safety limit to prevent infinite loops Need.for.speed.rivals-r.g. Mechanics File
except ValueError: print("Invalid input. n must be an integer.") except Exception as e: print(f"An error occurred: {e}") Fansly Bigmiche Aka | Little Susanna Big Miche Free
# Increase recursion depth for deep hierarchical calls sys.setrecursionlimit(2000)
# Successor Ordinal: f_alpha+1(n) = f_alpha^n(n) if isinstance(alpha, int) and alpha >= 0: # Iterate the function 'n' times result = n for _ in range(n): result = self._f(alpha - 1, result) return result return "Unknown Ordinal"
while True: user_input = input("Enter alpha (ordinal) and n (e.g., '2 3' for f_2(3)): ").strip() if user_input.lower() == 'exit': break try: parts = user_input.split() if len(parts) != 2: print("Please enter two values (alpha and n).") continue # Parse inputs alpha_in = parts[0] n_in = int(parts[1]) if alpha_in == 'w': alpha_val = 'w' else: alpha_val = int(alpha_in) print(f"\nCalculating f_{alpha_val}({n_in})...") # Attempt calculation if (isinstance(alpha_val, int) and alpha_val >= 3) or (alpha_val == 'w' and n_in > 2): print("Notice: This value is extremely large. Performing symbolic reduction only.") print(calc.symbolic_reduction(alpha_val, n_in)) print("(To compute actual values, use alpha < 3)\n") else: result = calc.calculate(alpha_val, n_in) print(f"Result: {result}\n")
Instead, an FGH calculator is best implemented as a . It takes a function definition and an input, and it applies the recursive rules until the expression is simplified or evaluated.